Transmission Lines

Characteristic Impedance Even

Pronunciation: /ˌkær.ək.təˈrɪs.tɪk ˈɪm.piː.dəns ˈiː.vən/
Characteristic Impedance Even ($Z_{0e}$) is the characteristic impedance of one transmission line in a coupled-line system when both lines are excited with identical, in-phase voltage signals (even-mode excitation).
Category: Transmission Lines

Understanding Characteristic Impedance Even

Even-Mode Excitation in Coupled Transmission Lines

When two transmission lines are placed close to each other on a printed circuit board (such as two parallel microstrip traces), their electromagnetic fields interact. This coupling modifies the wave propagation characteristics of the lines, creating a coupled-line system. To analyze these systems, engineers use modal analysis, which splits the propagation into two independent modes: the even mode and the odd mode. The Characteristic Impedance Even ($Z_{0e}$) is the impedance of one line under even-mode excitation.

Even-mode excitation occurs when both lines are driven with identical, in-phase signals ($V_1 = V_2$). Under these conditions, the voltage at any point along the lines is equal, and there is no potential difference between them. Consequently, no current flows through the mutual capacitance between the lines. The effective capacitance of each line decreases to its capacitance to ground, which increases the characteristic impedance ($Z_{0e} > Z_0$).

Role in Directional Coupler Design

The even-mode characteristic impedance is a fundamental parameter in the design of coupled-line devices, such as parallel-line directional couplers, Wilkinson power dividers, and bandpass filters. In a directional coupler, the coupling factor ($C$) and the system impedance ($Z_0$) are directly defined by the relationship between the even-mode impedance ($Z_{0e}$) and the odd-mode impedance ($Z_{0o}$).

For a coupler to remain matched to the system impedance (typically 50 ohms) at all ports, the geometric mean of the even and odd impedances must equal the system impedance ($Z_0 = \sqrt{Z_{0e} Z_{0o}}$). Designing these devices requires carefully controlling the trace widths and the coupling gap to achieve the precise $Z_{0e}$ and $Z_{0o}$ values needed for the target coupling factor, ensuring flat frequency response and high isolation.

Key Mathematical Relations

Z_{0e} = \sqrt{\frac{L}{C_p}} \quad \text{and} \quad Z_0 = \sqrt{Z_{0e} Z_{0o}} Where: - Z_{0e} = Even-mode characteristic impedance (ohms) - L = Inductance per unit length of one line (Henries/meter) - C_p = Capacitance per unit length of one line to the ground plane (Farads/meter, excluding mutual capacitance) - Z_0 = System characteristic impedance (typically 50 \$\Omega\$) - Z_{0o} = Odd-mode characteristic impedance (ohms)

Technical Specifications Comparison

Coupling Target (dB) System Impedance (\$Z_0\$) Required Even Impedance (\$Z_{0e}\$) Required Odd Impedance (\$Z_{0o}\$) Typical Trace Gap Width Spacing
3 dB (Hybrid Coupler) 50 \$\Omega\$ 120.7 \$\Omega\$ 20.7 \$\Omega\$ Extremely narrow gap (often requires broadside coupling)
10 dB Coupler 50 \$\Omega\$ 69.5 \$\Omega\$ 36.0 \$\Omega\$ Narrow gap (typical microstrip gap limits)
15 dB Coupler 50 \$\Omega\$ 60.1 \$\Omega\$ 41.6 \$\Omega\$ Medium gap spacing
20 dB Coupler 50 \$\Omega\$ 55.3 \$\Omega\$ 45.2 \$\Omega\$ Wide gap spacing (very loose coupling)
Common Questions

Frequently Asked Questions

Why is the even-mode impedance higher than the system impedance of a single line?

In even-mode excitation, both lines carry in-phase voltages. Because there is no potential difference between the lines, the mutual capacitance is not charged. The effective capacitance of the line decreases because the parallel mutual capacitance path is disabled. Since $Z_0 = \sqrt{L/C}$, a decrease in effective capacitance results in an increase in impedance.

What is the relationship between even-mode impedance and odd-mode impedance in a matched coupler?

For a coupled-line coupler to be matched to a system impedance ($Z_0$), the even-mode impedance ($Z_{0e}$) and the odd-mode impedance ($Z_{0o}$) must satisfy the matching condition: $Z_0^2 = Z_{0e} Z_{0o}$. This ensures that the ports do not reflect power when terminated with the system impedance.

How do you calculate the coupling coefficient using even and odd impedances?

The coupling coefficient ($k$, linear scale) is calculated using the formula: $k = (Z_{0e} - Z_{0o}) / (Z_{0e} + Z_{0o})$. The coupling factor in decibels is then $C = -20 \log_{10}(k)$. Tight coupling requires a large difference between $Z_{0e}$ and $Z_{0o}$, which requires placing the traces very close together.

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