Breakdown Voltage (Transistor)
Maximum voltage a transistor can sustain before avalanche failure
Definition & Physics
Breakdown voltage is the maximum voltage that can be applied across the output terminals of a transistor (drain-source for FETs, collector-emitter for BJTs/HBTs) before the electric field in the depletion region reaches the critical value for impact ionization. At this threshold, accelerated carriers generate electron-hole pairs through collisions with the crystal lattice, triggering an avalanche multiplication process that causes a rapid, uncontrolled increase in current.
For RF power transistors, breakdown voltage directly determines the maximum DC supply voltage and, consequently, the maximum RF output power. Since output power scales as VDD²/(2RL), a device with twice the breakdown voltage can theoretically deliver four times the output power for the same load impedance. This is why wide-bandgap semiconductors with high critical electric fields (GaN at 3.3 MV/cm, SiC at 2.5 MV/cm) dominate high-power RF applications: their high breakdown voltages allow high supply voltages, which produce more power from smaller devices with higher load impedances that are easier to match.
Key Formulas
Breakdown Voltage (1D approximation):
BV = Ecrit² × εs / (2 × q × Nd)
where Ecrit = critical field, εs = permittivity, Nd = doping
Johnson Figure of Merit:
JFM = (Ecrit × vsat) / (2π)
GaN JFM is ~27× silicon, enabling simultaneous high voltage and high frequency
Max Output Power:
Pmax = (BV − Vknee)² / (8 × Ropt)
Semiconductor Breakdown Comparison
| Technology | BVds/BVceo | Typical VDD | Ecrit (MV/cm) | Pdensity (W/mm) | fmax (GHz) |
|---|---|---|---|---|---|
| GaN-on-SiC | 80-200 V | 28-50 V | 3.3 | 5-10 | 40+ |
| GaN-on-Si | 60-100 V | 28 V | 3.3 | 3-5 | 20 |
| LDMOS | 65-130 V | 28-32 V | 0.3 | 1-2 | 4 |
| GaAs pHEMT | 15-25 V | 5-8 V | 0.4 | 0.5-1 | 40+ |
| InP HBT | 8-15 V | 4-6 V | 0.5 | 0.4 | 100+ |
| SiGe HBT | 5-12 V | 3-5 V | 0.3 | 0.3 | 50+ |
| Si CMOS | 3-7 V | 1.2-3.3 V | 0.3 | 0.1 | 30 |
Practical Application
When selecting a transistor for a 200 W L-band (1.2 GHz) solid-state radar transmitter, the designer needs sufficient breakdown voltage to handle class-AB operation with 10:1 VSWR ruggedness. A GaN HEMT with BVds = 150 V allows operation at VDD = 50 V with peak voltage of 100 V under matched conditions and 150 V under open-circuit mismatch. The optimum load resistance is Ropt = (50 − 5)² / (2 × 200) = 5.06 Ω, requiring an output matching network with a 10:1 impedance transformation ratio from 50 Ω. An LDMOS alternative with BVds = 110 V at VDD = 32 V would need Ropt = 2.3 Ω, requiring a much wider bandwidth-limiting 22:1 transformation.
Frequently Asked Questions
What is the difference between BVds and BVdss?
BVds is measured with the gate at pinch-off bias, while BVdss has the gate shorted to source (Vgs = 0). For depletion-mode FETs, BVdss is typically lower because the open channel provides a leakage path. Always check datasheet conditions.
How does temperature affect breakdown voltage?
Avalanche breakdown voltage has a positive temperature coefficient of ~0.05-0.1%/°C. A GaN device rated 120 V at 25°C may reach 126 V at 150°C. However, increased leakage current at temperature partially offsets this benefit and thermal runaway risk increases.
Why do GaN HEMTs have higher BV than GaAs?
GaN's critical field (3.3 MV/cm vs 0.4 MV/cm) from its wider bandgap (3.4 eV vs 1.42 eV) yields ~8× higher BVds at equivalent geometry. A 0.25 µm GaN HEMT achieves 80-120 V vs 15-20 V for GaAs.