Power Amplifier Design

Ballasting

/bal-uh-sting/
A thermal stabilization technique that places series resistors on individual emitter fingers (or gate sources) of paralleled RF transistor cells to equalize current distribution and prevent thermal runaway. As a cell heats up, its VBE drops (~2 mV/°C), drawing more current. The ballast resistor counteracts this by increasing the voltage drop across the hotter cell, forcing current redistribution. Typical emitter ballast values: 1-5 Ω for GaAs HBT, 0.5-2 Ω for SiGe. The cost is reduced gain and PAE from emitter degeneration.
HBT: 1-5 Ω
SiGe: 0.5-2 Ω
Penalty: Gain, PAE

Understanding Ballasting

In any multi-cell power amplifier, manufacturing variations and layout asymmetries cause slight differences in threshold voltage and thermal resistance between cells. Without ballasting, the cell with the lowest VBE (or hottest junction) draws disproportionate current. The resulting self-heating further reduces its VBE, attracting even more current in a positive feedback loop. This "current hogging" concentrates the entire array's current into one or a few cells, causing localized thermal destruction within milliseconds.

The problem is especially acute in GaAs HBT power amplifiers because GaAs has poor thermal conductivity (46 W/mK versus 150 W/mK for silicon), so heat generated in one cell does not spread efficiently to neighbors. GaN HEMTs on SiC substrates are less susceptible because SiC's thermal conductivity (490 W/mK) provides excellent heat spreading, and FETs have a positive temperature coefficient for drain current at typical bias points, providing inherent self-ballasting. Nevertheless, GaN PA designs with many paralleled fingers still benefit from source ballasting at high current densities.

Ballast Sizing Equations

Thermal stability criterion:
Rballast > (∂VBE/∂T) × Rth / Ncells
∂VBE/∂T ≈ -2 mV/°C

Practical sizing:
Rballast = ΔVBE / Icell
ΔVBE = 20-50 mV process spread
Icell = 10-20 mA per finger
Rballast = 1-5 Ω (emitter)

Gain penalty:
ΔG = -20 log(1 + gm × Rballast)
gm = 300 mS, R = 3 Ω: ΔG ≈ -5.6 dB

Base ballast equivalent:
Rbase = β × Remitter
β = 100: Rbase = 100-500 Ω

Ballasting Technique Comparison

TechniqueR ValueGain LossFeedback StrengthBest For
Emitter ballast1-5 Ω3-6 dBStrong (IC)GaAs HBT PAs
Base ballast50-200 Ω0.5-1 dBModerate (IB)SiGe PAs
Combined E+B1 Ω + 100 Ω1-3 dBStrongHigh-reliability
Thermal shuntN/A0 dBLayout-basedGaN on SiC
Adaptive biasActive circuit0-1 dBStrongMMIC PAs
Common Questions

Frequently Asked Questions

Why do paralleled RF transistors need ballasting?

Bipolar transistors have negative VBE temperature coefficient (-2 mV/°C). In a paralleled array, the hottest cell draws the most current, heats further, and can absorb the entire array's current within milliseconds. GaAs HBTs are especially vulnerable due to poor thermal conductivity (46 W/mK). Ballast resistors break this positive feedback by inserting a current-proportional voltage drop that raises the effective VBE of hotter cells.

How do you size the ballast resistor?

Rballast must exceed (∂VBE/∂T) × Rth / Ncells to guarantee stability. Practically, R = ΔVBE / Icell, where ΔVBE is the 20-50 mV process spread and Icell is per-finger current (10-20 mA). For a GaAs HBT at 15 mA, Rballast of 2-5 Ω is typical. The penalty: voltage headroom loss (I × R) and gain reduction from emitter degeneration.

What is the difference between emitter and base ballasting?

Emitter ballasting (1-5 Ω) senses collector current directly, providing strong feedback but degrading gain by 3-6 dB. Base ballasting (50-200 Ω) senses the smaller base current (IB = IC/β), preserving RF gain but requiring higher resistance. Combined designs use small emitter ballast for DC stability plus base ballast for margin, optimizing the reliability-performance tradeoff.

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