PCB Design

Annular Ring

A digital designer places a via with a massive 20-mil annular ring to guarantee the PCB manufacturer won't accidentally drill outside the copper pad. The board is mechanically indestructible. However, when an RF engineer pushes a 10 GHz signal through that same via, the massive copper pad acts as a parallel plate capacitor against the inner ground planes. The via's impedance drops from 50 ohms to 25 ohms, causing a massive reflection that ruins the return loss. If the RF engineer shrinks the pad to fix the impedance, the manufacturer's drill bit wanders, breaks out of the copper, and the via fractures during the first temperature cycle. In high-frequency PCB design, the annular ring is a constant, razor's-edge compromise between mechanical survival (IPC Class 3) and microwave transparency.
Category: PCB Design
Calculation: (Pad Diameter − Drill Diameter) / 2
RF Impact: Adds shunt capacitance

Annular Ring Rules & IPC Standards

Standard / ConditionRequirementApplication Consequence
IPC Class 2 (Consumer)90° Breakout allowedVia functions, but may fail under severe thermal stress
IPC Class 3 (Mil/Aero)2.0 mil (0.05mm) minimumGuarantees 360° intact copper ring, maximum reliability
Standard Drill Wander± 3 to 5 milsRequires pads to be 10 mils larger than the drill size
Laser Microvia± 1 mil wanderAllows ultra-small pads, critical for HDI and mmWave routing
TeardroppingRequired at trace junctionPrevents breakout from severing the trace connection
Annular Ring Calculation:
Ring = (Pad Diameter − Finished Hole Diameter) / 2
Example: 20 mil pad, 10 mil hole = 5 mil annular ring (assuming perfect centering).

RF Parasitic Capacitance Impact:
C ≈ (ε · A) / d
As the pad diameter (A) increases, the shunt capacitance to adjacent ground planes increases, lowering the via's characteristic impedance.
Common Questions

Frequently Asked Questions

Why does drill breakout happen?

Mechanical drill bits are not perfect. They deflect, machines have tolerances, and PCB laminates shift during pressing. A standard drill can wander up to 5 mils from center. If your pad isn't large enough to absorb this wander, the hole breaches the edge of the copper, weakening the via connection.

How does it affect RF impedance?

Every via is essentially a coaxial cable passing through the board. The via barrel is the center conductor. The anti-pad in the ground planes is the outer shield. A large annular ring adds bulk copper to the center conductor, acting like a shunt capacitor. This lowers the via impedance, causing VSWR degradation at high frequencies.

What are teardrops?

A teardrop is extra copper added to smooth the junction between a thin trace and a via pad. If a drill wanders exactly toward the incoming trace, it can sever the connection. The teardrop widens the landing area, protecting the electrical connection and reducing mechanical stress concentration.

PCB Manufacturing

Via Impedance Calculator

Enter your substrate dielectric, via diameter, anti-pad size, and annular ring dimensions. Calculate the resulting characteristic impedance of your signal via to ensure transparent high-frequency routing.

Calculate Via Impedance